okay, let's see how this type of contest goes. The first person to post the correct answer receives 3 presents with random gifts inside.

Only 1 guess per person, editing your post is okay in this contest, but it's the time stamp that will determine the winner. The earliest person to correctly answer wins the prize.

Good luck everyone!!


Here is the question:

Nine individual pieces of paper can be numbered, so that the sum of the numbers on 2 randomly chosen pieces of paper totals to an integer from 2 to 12 with the same frequency as rolling two standard dice. What are the numbers on the nine pieces of paper?

Correct solutions will consist of the 9 values found on the 9 pieces of paper.

12 i dont no

Edited on 07-06-2005 05:47

the numbers on the nine pieces of paper can be any number from 1-6

122344566

Edited on 07-06-2005 22:17

1, 1, 2, 2, 3, 4, 5, 6, 6

7

2,3,4,5,6,7,8,9,10

123456789 da da! iii think...

1,1,1,2,2,2,3,3,3

2,1,1,1,2,2,3,1

1,1,2,3,3,4,5,6,6

3,3,1,1,4,4,8,8

I sware to god that this is impossible, even when you use negertives and 0 I don't think that thaer is a permutation that succeads.

0 and minas numbers can be used.

I've been beaten so im offering this advice openly to help anybody else simply because I want the awanser to surpress my curiosity.

Edited on 07-06-2005 22:45

OK I had another look and came up with this, not sure about it but I think i'm on the right lines.

0.5 1.5 2.5 2.5 3.5 4.5 4.5 5.5 6.5

PS: sorry for all the edits, I got this awanser at 9:53 GMT if it helps.

Edited on 07-06-2005 22:54

Congrats Gelgarin! it took longer than I thought for someone to solve this.

message me in game, and we'll meet up to exchange your presents!